eix = cos(x) + i*sin(x)
This can easily be shown to be true by replacing cos(x) and sin(x) with their respective formulations and simplifying.
sin(x) = (exi - e-xi)/2i
cos(x) = (exi + e-xi)/2
eix = (exi + e-xi)/2 + i*(exi - e-xi)/2i
eix = (exi + e-xi)/2 + (exi - e-xi)/2
eix = (exi + exi)/2
eix = 2exi/2
eix = exi
What's It Good For?
| eix | Calculating ln(i) |
| Euler's Equation Explained By Dr. Math |


